Mathematics for Fun: Find the magnitude and the direction angle

Find the magnitude and the direction angle (to the nearest tenth) for the vector

$\f[\left<3, 3 \right>\f]$
1. Magnitude:
Formula: $\f[\left|\left|v \right| \right|=\sqrt{x^{2}+y^{2}}\f]$
$\f[\left|\left|3, 3 \right| \right| = \sqrt{3^{2}+3^{2}} = \sqrt{9+9}=\sqrt{18}= 3\sqrt{2}\f]$

2. Direction Angle:
Formula: $\f[\theta = \tan^{-1} \frac{y}{x}\f]$
Graph the vector: