Showing posts with label vector. Show all posts
Showing posts with label vector. Show all posts

Thursday, October 27, 2011

Find the magnitude and the direction angle

Find the magnitude and the direction angle (to the nearest tenth) for the vector
\f[\left<3, 3 \right>\f]
1. Magnitude:
Formula: 
\f[\left|\left|v \right| \right|=\sqrt{x^{2}+y^{2}}\f]
\f[\left|\left|3, 3 \right| \right| = \sqrt{3^{2}+3^{2}} = \sqrt{9+9}=\sqrt{18}= 3\sqrt{2}\f]

2. Direction Angle:
Formula: 
\f[\theta = \tan^{-1} \frac{y}{x}\f]
Graph the vector:
Find the direction angle:\f[\tan \theta =\frac{3}{3} = 1\f]
\f[\tan^{-1} (1) = 45\deg \f]
Final results:
Magnitude 3√2
Direction angle 45 °

Images for my math classes